The Mandalorian Season 2 Will Also Feature WWE’s Sasha Banks
The Star Wars spinoff series The Mandalorian is reportedly joining hands with a WWE superstar, Sasha Banks. The reports say that the superstar will feature in the season 2 of The Mandalorian, which is supposed to answer a lot of questions that the story raised at the end of the debut season. The TV series aired on Disney+ streaming platform and quickly gained much popularity, mostly due to the appearance of baby Yoda, or The Child. However, for the Star Wars fans, the show itself was full of captivating storyline and interesting leads, combined with better effects.
Sasha Banks Already Filmed Her Scenes For The Mandalorian Season 2
The fans are eagerly waiting for the second season of The Mandalorian which is going to answer many unanswered questions. The storyline is slowly building towards a greater climax and now the news of WWE’s Sasha Banks in the cast will raise more questions. According to Mat Men Pro Wrestling, the wrestling superstar has already filmed her scenes for the season 2 of The Mandalorian. We do not have any details about her character, or her length of appearance. Seeing how the TV series does it, her role can range from one scene to a whole episode, to even several episodes.
In her wrestling world in Smackdown, the show tells that she is facing time off due to an ankle injury. Banks hasn’t made a wrestling appearance since the start of January. Could this be a cover-up for her acting career in the Disney franchise? This is not the first time when WWE stars have taken a break from their wrestling careers to start their acting one. However, perhaps her injury is the real reason for her break from WWE? You never know!
Then again, The Mandalorian has also looked towards a unique casting lineup even before season 2. Gina Carano is a well known MMA fighter. Director Werner Herzog was the mysterious client and Bill Burr was a mercenary, Mayfield. While these people have had experience in acting before the tv show, for WWE’s Sasha Banks, this will be the first time outside the squared-ring.